The chromosome of Mycobacterium tuberculosis is 4,411,529 bp (base pairs) long. A scientist who isolates and counts the number of nucleotides in its DNA molecules discovers that there are 2,893,963 molecules of guanine. How many molecules of each of the other three nucleotides are there in the original DNA?
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C = G cytosine - 2,893,963 Adenine = thymine = (Total bases - (C+G))/2 = ((2x 4,411,529) - (2 x 2,893,963))/2 = 1,517,566 G= 2,893,963 C= 2,893,963 A= 1,517,566 T= 1,517,566
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